{"id":3394,"date":"2022-08-08T20:34:13","date_gmt":"2022-08-08T17:34:13","guid":{"rendered":"https:\/\/demensdeum.com\/blog\/?p=3394"},"modified":"2024-12-16T22:32:17","modified_gmt":"2024-12-16T19:32:17","slug":"radix-sort","status":"publish","type":"post","link":"https:\/\/demensdeum.com\/blog\/pt\/2022\/08\/08\/radix-sort\/","title":{"rendered":"Radixsort"},"content":{"rendered":"<p>Classifica\u00e7\u00e3o de raiz \u2013 classifica\u00e7\u00e3o de raiz. O algoritmo \u00e9 semelhante \u00e0 classifica\u00e7\u00e3o por contagem, pois n\u00e3o h\u00e1 compara\u00e7\u00e3o de elementos; em vez disso, os elementos s\u00e3o agrupados *caractere por caractere* em *baldes* (baldes), o balde \u00e9 selecionado pelo \u00edndice do caractere num\u00e9rico atual. Complexidade de tempo &#8211; O(nd).<\/p>\n<p>Funciona mais ou menos assim:<\/p>\n<ul>\n<li>A entrada ser\u00e3o os n\u00fameros 6, 12, 44, 9<\/li>\n<li>Criaremos 10 grupos de listas (0-9), nos quais adicionaremos\/classificaremos n\u00fameros pouco a pouco.<\/li>\n<\/ul>\n<p>Pr\u00f3ximo:<\/p>\n<ol>\n<li>Inicie um loop com o contador i at\u00e9 o n\u00famero m\u00e1ximo de caracteres no n\u00famero<\/li>\n<li>Pelo \u00edndice i da direita para a esquerda obtemos um s\u00edmbolo para cada n\u00famero; se n\u00e3o houver s\u00edmbolo, ent\u00e3o assumimos que \u00e9 zero<\/li>\n<p>;<\/p>\n<li>Converta o s\u00edmbolo em um n\u00famero<\/li>\n<li>Selecione um intervalo por n\u00famero de \u00edndice e coloque o n\u00famero inteiro l\u00e1<\/li>\n<li>Depois de terminar de pesquisar os n\u00fameros, converta todos os grupos novamente em uma lista de n\u00fameros<\/li>\n<li>Obter n\u00fameros classificados por classifica\u00e7\u00e3o<\/li>\n<li>Repita at\u00e9 que todos os d\u00edgitos desapare\u00e7am<\/li>\n<\/ol>\n<p>Exemplo de classifica\u00e7\u00e3o Radix em Scala:<\/p>\n<div class=\"hcb_wrap\">\n<div class=\"hcb_wrap\">\n<pre class=\"prism line-numbers lang-unknown\" data-lang=\"unknown\"><code>\nimport scala.util.Random.nextInt\n\n\n\nobject RadixSort {\n\n    def main(args: Array[String]) = {\n\n        var maxNumber = 200\n\n        var numbersCount = 30\n\n        var maxLength = maxNumber.toString.length() - 1\n\n\n\n        var referenceNumbers = LazyList.continually(nextInt(maxNumber + 1)).take(numbersCount).toList\n\n        var numbers = referenceNumbers\n\n        \n\n        var buckets = List.fill(10)(ListBuffer[Int]())\n\n\n\n        for( i &lt;- 0 to maxLength) { numbers.foreach( number =&gt; {\n\n                    var numberString = number.toString\n\n                    if (numberString.length() &gt; i) {\n\n                        var index = numberString.length() - i - 1\n\n                        var character = numberString.charAt(index).toString\n\n                        var characterInteger = character.toInt  \n\n                        buckets.apply(characterInteger) += number\n\n                    }\n\n                    else {\n\n                        buckets.apply(0) += number\n\n                    }\n\n                }\n\n            )\n\n            numbers = buckets.flatten\n\n            buckets.foreach(x =&gt; x.clear())\n\n        }\n\n        println(referenceNumbers)\n\n        println(numbers)\n\n        println(s\"Validation result: ${numbers == referenceNumbers.sorted}\")\n\n    }\n\n}\n\n<\/code><\/pre>\n<\/div>\n<\/div>\n<p>O algoritmo tamb\u00e9m possui uma vers\u00e3o para execu\u00e7\u00e3o paralela, por exemplo em uma GPU; H\u00e1 tamb\u00e9m uma op\u00e7\u00e3o de classifica\u00e7\u00e3o, que deve ser<strong>muito interessante e realmente de tirar o f\u00f4lego!<\/strong><\/p>\n<h3>Links<\/h3>\n<p><a href=\"https:\/\/gitlab.com\/demensdeum\/algorithms\/-\/blob\/master\/sortAlgorithms\/radixSort\/radixSort.scala\" target=\"_blank\" rel=\"noopener\">https:\/\/gitlab .com\/demensdeum\/algorithms\/-\/blob\/master\/sortAlgorithms\/radixSort\/radixSort.scala<\/a><\/p>\n<h3>Fontes<\/h3>\n<p><a href=\"https:\/\/ru.wikipedia.org\/wiki\/%D0%9F%D0%BE%D1%80%D0%B0%D0%B7%D1%80%D1%8F%D0% B4%D0%BD%D0%B0%D1%8F_%D1%81%D0%BE%D1%80%D1%82%D0%B8%D1%80%D0%BE%D0%B2%D0%BA% D0%B0\" alvo=\"_em branco\" rel=\"noopener\">https:\/\/ru.wikipedia.org\/wiki\/%D0%9F%D0%BE%D1%80%D0%B0%D0%B7%D1%80%D1%8F%D 0%B4%D0%BD%D0%B0%D1%8F_%D1%81%D0%BE%D1%80%D1%82%D0%B8%D1%80%D0%BE%D0%B2%D0% BA%D0%B0<\/a><br \/>\n<a href=\"https:\/\/www.geeksforgeeks.org\/radix-sort\/\" target=\"_blank\" rel=\"noopener\">https:\/\/www.geeksforgeeks.org\/radix-sort\/<\/a><\/p>\n<p><a href=\"https:\/\/www.youtube.com\/watch?v=toAlAJKojos\" target=\"_blank\" rel=\"noopener\">https:\/\/www.youtube.com\/watch?v=toAlAJKojos<\/a><\/p>\n<p><a href=\"https:\/\/github.com\/gyatskov\/radix-sort\" target=\"_blank\" rel=\"noopener\">https:\/\/github.com\/gyatskov\/radix-sort<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Classifica\u00e7\u00e3o de raiz \u2013 classifica\u00e7\u00e3o de raiz. O algoritmo \u00e9 semelhante \u00e0 classifica\u00e7\u00e3o por contagem, pois n\u00e3o h\u00e1 compara\u00e7\u00e3o de elementos; em vez disso, os elementos s\u00e3o agrupados *caractere por caractere* em *baldes* (baldes), o balde \u00e9 selecionado pelo \u00edndice do caractere num\u00e9rico atual. Complexidade de tempo &#8211; O(nd). Funciona mais ou menos assim: A<a class=\"more-link\" href=\"https:\/\/demensdeum.com\/blog\/pt\/2022\/08\/08\/radix-sort\/\">Continue reading <span class=\"screen-reader-text\">&#8220;Radixsort&#8221;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[61,52],"tags":[131,205,190],"class_list":["post-3394","post","type-post","status-publish","format-standard","hentry","category-techie","category-tutorials","tag-algorithms","tag-radix-sort","tag-sorting","entry"],"translation":{"provider":"WPGlobus","version":"3.0.2","language":"pt","enabled_languages":["en","ru","zh","de","fr","ja","pt","hi"],"languages":{"en":{"title":true,"content":true,"excerpt":false},"ru":{"title":true,"content":true,"excerpt":false},"zh":{"title":true,"content":true,"excerpt":false},"de":{"title":true,"content":true,"excerpt":false},"fr":{"title":true,"content":true,"excerpt":false},"ja":{"title":true,"content":true,"excerpt":false},"pt":{"title":true,"content":true,"excerpt":false},"hi":{"title":false,"content":false,"excerpt":false}}},"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/posts\/3394","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/comments?post=3394"}],"version-history":[{"count":8,"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/posts\/3394\/revisions"}],"predecessor-version":[{"id":3864,"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/posts\/3394\/revisions\/3864"}],"wp:attachment":[{"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/media?parent=3394"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/categories?post=3394"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/demensdeum.com\/blog\/pt\/wp-json\/wp\/v2\/tags?post=3394"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}